Answer:
A. 40 combinations
we have 8 x 5 = 40
Step-by-step explanation:
Would be 60 as 3 letter words with 5 letters.
The logic is that all letters are being used to their maximum and with numbers 3 within 5 or 5 within 5 the maximum that cna be used is 12 rotation for 3 per letter or 8 rotaion for 5. Then we have 5 rotations = 60 for 3 and 40 for 5. Another logic is the many combinations can you make from the numbers 1 2 3 4 5 not multiplying?
The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.
We see that 4+3 +2+1 = 10 and shows less than 5 number combinations at 120, and then we have 5
5:10 ratio = 5/15 = 1/3
This = 1/3 of 120 =40
Then we find answer is 40 as compact 5 letter words from the word tight.
Answer:
141000 * (1 - 0.016)^15 = 110699.48 = A 110700
Step-by-step explanation:
1st year depreciation = 141000 - (141000 * 0.016) = 138744
2nd year depreciation = 138744 - (138744 * 0.016) = 136524.096
3rd year depreciation = 136524.096 - (136524.096 * 0.016) = 134339.710464
etc. unitl you reach the 15th year
Basically we calculate 1.6% of the current value of the house and subtract that from the current value for each year for 15 years.
The equation used in the answer is a faster way to approach your answer instead of calculating for each year.
You'd multiply your initial value by the difference in percentage (note well that since it is decreasing in value we subtract the decimal equivalent to 1.6% which is 0.016, from 1 where one represents 100% and then raise the difference gained to the power of the amount of years which would be 15.
Answer:
For 4 years the money was in the account .
Step-by-step explanation:
Formula

As given
Bonita deposited 1300 into a bank account that earned 5.75% simple interest each year.
She earned $299 in interest before closing the account.
Principle = $1300
Rate = 5.75%
Simple interest = $299
Putting all the values in the formula




Time = 4 years
Therefore for 4 years the money was in the account .
Answer:
A polynomial can't have more roots than the degree. So, a sixth degree polynomial, has at most 6 distinct real roots. I may be wrong
Step-by-step explanation:
no step