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Whitepunk [10]
3 years ago
8

Scott takes gets a student loan

Mathematics
2 answers:
densk [106]3 years ago
6 0
I’m confused. This doesn’t mean anything
andrezito [222]3 years ago
4 0

Answer:

what?

Step-by-step explanation:

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Find the interest on naira 40000.00 for 2 years at 20% per annum compound interest. Please I need the answer ASAP
andrey2020 [161]

Given:

Principal value = 40000

Rate of compounded interest = 20%

Time = 2 years

To find:

The interest.

Solution:

Formula for amount is

A=P\left(1+\dfrac{r}{100}\right)^t

Where, P is principal, r is rate of interest and t is time in years.

Putting the given values, we get

A=40000\left(1+\dfrac{20}{100}\right)^2

A=40000\left(1+\dfrac{1}{5}\right)^2

A=40000\left(\dfrac{6}{5}\right)^2

A=40000\left(\dfrac{36}{25}\right)

A=57600

Now, the formula for interest is

I=A-P

I=57600-40000

I=17600

Therefore, the amount of compound interest is 17,600.

7 0
3 years ago
Please help im in a rush
serious [3.7K]

Answer:

a)

Surface Area: 172 cm^2

Volume: 112 cm^3

b) Surface Area

c) Volume

Step-by-step explanation:

6 0
2 years ago
According to a bridal magazine, the average cost of a wedding reception for an American wedding is $8213. Assume that this avera
Thepotemich [5.8K]

Answer:

a. The point estimate of the corresponding population mean is of $8213.

b. The margin of error is of $103.

c. The 98% confidence interval for the corresponding population mean is between $7973.5 and $8452.5, which means that for all weedings, we are 98% sure that the true population mean is in this interval.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. What is the point estimate of the corresponding population mean?

The sample mean is of $8213. So, by the Central Limit Theorem, the point estimate of the corresponding population mean is of $8213.

b. What is the margin of error for this estimate (use2 standard deviations (divided by Vn) to either side of the mean is used when no specific confidence level is stated).

Sample of 450, standard deviation of $2185. So

M = \frac{2185}{\sqrt{450}} = 103

The margin of error is of $103.

c. Create and interpret a 98% confidence interval for the corresponding population mean.

The confidence interval is given by:

\mu \pm M*z

In which \mu is the sample mean and z is the value related to the confidence level.

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.325.

Then

\mu - M*z = 8213 - 2.325*103 = 7973.5

\mu + M*z = 8213 + 2.325*103 = 8452.5

The 98% confidence interval for the corresponding population mean is between $7973.5 and $8452.5, which means that for all weedings, we are 98% sure that the true population mean is in this interval.

4 0
3 years ago
The equation of the line of best fit of a scatter plot is y = −7x − 2. What is the the y-intercept?
kobusy [5.1K]

Answer:

i think its (0,-2)

Step-by-step explanation:

6 0
3 years ago
In February, Alec had 1,568 visitors to his website. In March, he had 1,335 visitors to his website. What is the percentage decr
shusha [124]

Answer:7.5%

Step-by-step explanation:

decrease the number of visitors from Alec´s website from February to the next month.

4 0
3 years ago
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