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Kipish [7]
3 years ago
11

Help me please on my homework it's due today!

Mathematics
2 answers:
Eva8 [605]3 years ago
8 0
The answer is D. $756
Nataliya [291]3 years ago
7 0
126/6 = 21
So, each ticket is $21.
14*21 = 294
So, 14 tickets add up to $294.
You might be interested in
A car traveld 32 miles in 4 hours at this rate how many miles will the car travel in 0.5 hours
Mandarinka [93]

Answer:

4 miles

Step-by-step explanation:

In order to find how many miles the car will travel in 0.5 hours, we can set up a proportion.

\frac{32}{4} = \frac{x}{0.5}

We can now cross multiply to find the value of x.

32 \cdot 0.5 = 16\\\\16\div4 = 4

So the car can travel 4 miles in 0.5 hours.

Hope this helped!

5 0
3 years ago
Read 2 more answers
1.6022x 10-19 round three decimal places
den301095 [7]

Answer:

1.6022x 10-19

Step-by-step explanation:

1.6022x 10-19 then simplifies into 16.022 because of the 10, and then the final answer is -2.978

6 0
3 years ago
Read 2 more answers
Select all the equations on which the point (10,0) lies.
Makovka662 [10]

Answer:

  B, C

Step-by-step explanation:

Since y=0, you are looking for equations such that 10 times the coefficient of x is the constant in the equation.

  a) 5·10 ≠ 15

  b) 2·10 = 20 . . . . select this one

  c) 10 = 10 . . . . select this one

  d) 3·10 ≠ 13

  e) 4·10 ≠ 20

  f) 6·10 ≠ 50

8 0
2 years ago
How can I solve (n+1) x 2= 10 <br> Please someone answer :(
Ray Of Light [21]
(n+1)x 2=10 
2n+2=10 
2n=8
n=4
4 0
3 years ago
Read 2 more answers
A group of people were asked if they had run a red light in the last year. 290 responded "yes", and 177 responded "no". Find the
GuDViN [60]

Answer:

0.621

Step-by-step explanation:

Number of people that have run a red light in the last year = 290

Number of people that have not run a red light in the last year = 177

Total number of respondents = 290 + 177

                                                 = 467

Pr(if a person is chosen at random, they have run a red light in the last year) = \frac{number of people who has run the red light last year}{total number of respondents}

                   = \frac{290}{467}

                   = 0.621

The probability that if a person is chosen at random, they have run a red light in the last year is 0.621.

6 0
3 years ago
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