Answer:
-1,512,390
Step-by-step explanation:
Given
a1 = 15

Let us generate the first three terms of the sequence

For 

Hence the first three terms ae 15, 8, 1...
This sequence forms an arithmetic progression with;
first term a = 15
common difference d = 8 - 15 = - -8 = -7
n is the number of terms = 660 (since we are looking for the sum of the first 660 terms)
Using the formula;
![S_n = \frac{n}{2}[2a + (n-1)d]\\](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D%5C%5C)
Substitute the given values;
![S_{660} = \frac{660}{2}[2(15) + (660-1)(-7)]\\S_{660} = 330[30 + (659)(-7)]\\S_{660} = 330[30 -4613]\\S_{660} = 330[-4583]\\S_{660} = -1,512,390](https://tex.z-dn.net/?f=S_%7B660%7D%20%3D%20%5Cfrac%7B660%7D%7B2%7D%5B2%2815%29%20%2B%20%28660-1%29%28-7%29%5D%5C%5CS_%7B660%7D%20%3D%20330%5B30%20%2B%20%28659%29%28-7%29%5D%5C%5CS_%7B660%7D%20%3D%20330%5B30%20-4613%5D%5C%5CS_%7B660%7D%20%3D%20330%5B-4583%5D%5C%5CS_%7B660%7D%20%3D%20-1%2C512%2C390)
Hence the sum of the first 660 terms of the sequence is -1,512,390
Step-by-step explanation:
BRAINLY FREE POINTS JSJJSJJ
Answer:
A
Step-by-step explanation:
The function is a quadratic whose graph is a parabola. All parabolas have no limitations on their domain. This means the domain of the function is all real numbers.
This parabola has a minimum value since its leading coefficient is positive. Its vertex is at (0,-2). This means its range is all values greater than -2 or y ≥ -2.
An inverse of a function is its reflection across the y=x line. This results in (x,y) in the function becoming (y,x) in its inverse. The domain of the function becomes the range of the inverse and the range of the function becomes the domain of the inverse. Inverse has x ≥ -2 as its domain and all real numbers for its range.
Answer:
396
Step-by-step explanation:
First, find the prime factorization of each number.
44 = 2^2 * 11
36 = 2^2 * 3^2
For the LCM, you need non-common factors and common factors with the larger exponent. Then you multiply together all the factors you use.
2 is a common factor. Both numbers have 2^2, so choose 2^2.
3 is not common. Use 3^2.
11 is not common. Use 11.
LCM = 2^2 * 3^2 * 11 = 396
If we have a less than (or less than or equal to) sign with an absolute value, that indicates a conjunction where values can be expressed as an interval. The absolute value will be less than the number to the right, but it will also at the same time be greater than the negative of the number to the right. Don't forget that absolute value is a distance measurement, and the distance from the origin to -4 is 4 units, just like the distance from the origin to +4 is 4 units. Our particular absolute value will look like this:
![\left[\begin{array}{ccc}x-6\end{array}\right] \leq 4](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx-6%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleq%204)
and
![\left[\begin{array}{ccc}x-6\end{array}\right] \geq -4](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx-6%5Cend%7Barray%7D%5Cright%5D%20%20%5Cgeq%20-4)
. Solving the first absolute value we have that

and the second one is

. In interval notation we need to put x between the 2 inequality signs, which will look like this:

. And there you go!