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PtichkaEL [24]
3 years ago
10

A two-factor study with two levels of factor A and three levels of factor B uses a separate group of n = 5 participants in each

treatment condition. How many participants are needed for the entire study?​
Mathematics
1 answer:
Mashcka [7]3 years ago
7 0

Answer: There are 30 participants are needed for the entire study.

Step-by-step explanation:

Since we have given that

Number of levels of factor A = 2

Number of levels of factor B = 3

Number of participants in each treatment condition = 5

So, the number of participants are needed for the entire study is given by

2\times 3\times 5\\\\=6\times 5\\\\=30

Hence, there are 30 participants are needed for the entire study.

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Use technology to find the line of best fit for the following data.
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Given:

The data points are:

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To find:

The equation of best fit line in the form of y=mx+b and then find the value of b.

Solution:

The general form of best fit line is:

y=mx+b              ...(i)

Where, m is the slope of best fit line and b is the y-intercept of the line.

Using the graphing calculator, we get the equation for the best fit line and the equation is

y=1.1x-0.7          ...(ii)

On comparing (i) and (ii), we get

b=-0.7

Therefore, the value of b is equal to -0.7.

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3 years ago
The number of hours per week that the television is turned on is determined for each family in a sample. The mean of the data is
Zigmanuir [339]
I don’t know skip that question
7 0
2 years ago
Total profit P is the difference between total revenue R and total cost C. Given the following​ total-revenue and​ total-cost fu
gavmur [86]

Answer:

The profit function is:

P(x)=-x^2+1280x-3300

The maximum value is 406, 300 occurring when x = 640.

Step-by-step explanation:

The revenue function is:

R(x)=1300x-x^2

And the cost function is:

C(x)=3300+20x

Then the total profit function will be:

P(x)=R(x)-C(x)=(1300x-x^2)-(3300+20x)=-x^2+1280x-3300

This is a quadratic function.

Therefore, the maximum value of the total profit will occur at its vertex point.

The vertex of a quadratic is given by:

\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)

In this case, a = -1, b = 1280, and c = -3300.

Then the point at which the maximum profit occurs is at:

\displaystyle x=-\frac{1280}{2(-1)}=640

And the maximum profit will be:

P(640)=-(640)^2+1280(640)-3300=406300

5 0
3 years ago
Read 2 more answers
An open box with a square base is to have a volume of 18 ft^3.
kotegsom [21]

Answer:

2.29 ft of side length and 1.14 height

Step-by-step explanation:

a) Volume V = x2h, where x is side of square base and h is hite.

Then surface area S = x2 + 4xh because box is open.

b) From V = x2h = 6 we have h = 6/x2.

Substitude in formula for surface area: S = x2 + 4x·6/x2, S = x2 + 24/x.

We get S as function of one variable x. To get minimum we have to find derivative S' = 2x - 24/x2 = 0, from here 2x3 - 24 = 0, x3 = 12, x = (12)1/3 ≅ 2.29 ft.

Then h = 6/(12)2/3 = (12)1/3/2 ≅ 1.14 ft.

To prove that we have minimum let get second derivative: S'' = 2 + 48/x3, S''(121/3) = 2 + 48/12 = 6 > 0.

And because by second derivative test we have minimum: Smin = (12)2/3 + 4(12)1/3(12)1/3/2 = 3(12)2/3 ≅ 15.72 ft2

5 0
2 years ago
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