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user100 [1]
3 years ago
14

I NEED HELP ASAP ⚠️⚠️ If 1 is a solution to g(x) = 0, what is the other solution?

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

9514 1404 393

Answer:

  A.  -1

Step-by-step explanation:

The table shows that g(x) = 0 for x = -1.  (third row)

The other solution is x = -1.

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PLEASE HELP! <br><br>Identify the y-intercept and zeros of <br>y = x^4 - 9x^2 - 36<br>Algebraically​
const2013 [10]

Answer:

Our y-intercept is (0, -36).

Our real zeros are: (-2√3, 0) and (2√3, 0)

And our imaginary zeros are: (i√3, 0) and (-i√3, 0)

Step-by-step explanation:

We have the function:

y=x^4-9x^2-36

Let's identify the y- and x-intercepts.

Y-Intercept:

To determine the y-intercept, we will substitute 0 for x and solve for y. So:

y=(0)^4-9(0)^2-36

Evaluate:

y=-36

Therefore, our y-intercept is at (0, -36).

X-Intercepts:

To determine our x-intercepts, we need to substitute 0 for y and solve for x. So:

0=x^4-9x^2-36

Now, we can factor. Before doing so, we can make the factored easier to see by converting this into quadratic form. Let's let u=x². Then:

0=(u^2)^2-9(x^2)-36

Substitute:

0=u^2-9u-36

Now, let's factor. We can use -12 and 3. So:

0=u^2+3u-12u-36 \\ 0=(u(u+3)-12(u+3)) \\ 0=(u-12)(u+3)

Now, we can substitute back u:

0=(x^2-12)(x^2+3)

Zero Product Property:

x^2-12=0\text{ or } x^2+3=0

Solve for x in each case:

x^2=12 \text{ or } x^2=-3

Take the square root of both sides. Since we're taking an even root, we will need plus/minus. Therefore:

x=\pm\sqrt{12}=\pm2\sqrt{3}\text{ or } x=\pm\sqrt{-3}=\pm i\sqrt{3}

Therefore, our zeros (both real and imaginary) are: (2√3, 0), (-2√3, 0), (i√3, 0), and (-i√3, 0)

5 0
3 years ago
How do u solve 14 times 14
alexgriva [62]
14x14=196 just add 14 +14 +14 +14 14 +14 14 +14 14 +14 14 +14 14 +14 and get 196
4 0
3 years ago
The lees rented a car for 4 weeks.The santos rented a car for 2 weeks.Whose weekly rentsl cost was lower?
Romashka-Z-Leto [24]
The santos because they rented the car for two weeks, while the others rented for four.
5 0
3 years ago
Read 2 more answers
What is the quotient of 3/4 and 5/6
Musya8 [376]

Answer:

9/10

Step-by-step explanation:

8 0
3 years ago
Suppose the rate of type II diabetes in 40- to 59-year-olds is 7% among Caucasians, 10% among African-Americans, 12% among Hispa
melomori [17]

Answer:

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

Step-by-step explanation:

We have these following rates of type II diabetes:

7% among Caucasians

10% among African-Americans

12% among Hispanics

5% among Asian-Americans.

The ethnic distribution of Houston is:

30% Caucasian

25% African-American

40% Hispanic

5% Asian-American

What is the overall probability of type II diabetes among 40- to 59-year-olds in Houston?

P = P_{1} + P_{2} + P_{3} + P_{4}

P_{1} is the probability of finding a Caucasian with type II diabetes in Houston. So it is 7% of 30%.

P_{1} = 0.07*0.30 = 0.021

P_{2} is the probability of finding an African-American with type II diabetes in Houston. So it is 10% of 25%.

P_{2} = 0.1*0.25 = 0.0215

P_{3} is the probability of finding a Hispanic with type II diabetes in Houston. So it is 12% of 40%.

P_{3} = 0.12*0.40 = 0.048

P_{4} is the probability of finding an Asian-American with type II diabetes in Houston. So it is 5% of 5%.

P_{3} = 0.05*0.05 = 0.0025

P = P_{1} + P_{2} + P_{3} + P_{4} = 0.021 + 0.0215 + 0.048 + 0.0025 = 0.093

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

4 0
4 years ago
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