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Sergio [31]
3 years ago
14

Need help with questions like this please message me if you can help

Mathematics
1 answer:
natulia [17]3 years ago
8 0
9x^2-4x-3 and x=-2

= 9*(-2)^2 - 4*-2 - 3
= (9*4)+8-3
= 36+8-3
= 44-3
=41
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Find a third-degree polynomial function with real coefficients and with zeros at -4 and -3 5i
Charra [1.4K]

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3 0
3 years ago
To factor 9x^2 - 4, you can first rewrite the expression as:
olga2289 [7]

Answer:

  C. (3x)^2 - (2)^2

Step-by-step explanation:

Each of the two terms is a perfect square, so the factorization is that of the difference of squares. Rewriting the expression to ...

  (3x)^2 - (2)^2

highlights the squares being differenced.

__

We know the factoring of the difference of squares is ...

  a^2 -b^2 = (a -b)(a +b)

so the above-suggested rewrite is useful for identifying 'a' and 'b'.

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Step-by-step explanation:

I got it right on Edge.

7 0
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