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Sergio [31]
3 years ago
14

Need help with questions like this please message me if you can help

Mathematics
1 answer:
natulia [17]3 years ago
8 0
9x^2-4x-3 and x=-2

= 9*(-2)^2 - 4*-2 - 3
= (9*4)+8-3
= 36+8-3
= 44-3
=41
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Given the sum s20= 910 of an arithmetic sequence and A20 = 95, Find A1​
Inessa05 [86]

Step-by-step explanation:

Sn=n/2(2a+(n-1)d)

910=n/2{2a+(n-1)d}

1820=n{2a+(n-1)d}

1820=20{2a+(20-1)d}

1820=20{2a+19d}

91=2a+19d

An=a+(n-1)d

95=a+(20-1)d

95=a+19d

91=2a+19d

---------------

4=-a

a=-4

91=2a+19d

91=2(-4)+19d

91=-8+19d

91+8=19d

99=19d

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A=-4

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3 years ago
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3 years ago
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