We can verify this with the graph
(-6, 3) NO
(-3, 3) NO
(-5, 0) NO
(-4, 2) YES
(0,0) NO
(-6, 6) YES
(-3, -6) NO
(-4.0) YES
the area where the solutions are in the yellow area
Answer:
C. 39.6
<em>good luck, i hope this helps :)</em>
I think the answer is C that what i think ;;:;/)
A) - 14 is the correct answer
Answer:
80/81
Step-by-step explanation:
If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.
The probability of getting at least 1 head involves 4 scenarios:
1) 1 Head and 3 Tails
2) 2 Heads and 2 Tails
3) 3 Heads and 1 Tail
4) 4 Heads
Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:
P(at least one head) + P(no heads) = 1
Then, P(at least one head) = 1 - P(no heads)
The probability of 4 tails is:
P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81
Then, P(at least one head) = 1 - 1/81=80/81
