Answer:
2.
A. (P+h)(x)
2x/x+4 (x-1) + x/x-1 (x+4)
2x^2-1/x^2-4
+
X^2+4/x^2-4
= 3x^2+3/x^2-4
B. (F-g)(x)
X^2-7x+6-x - 6
= x^2 -8x
C. (Fg)(x)
(X^2-7x+6)(x-6)
= x^3-13x^2+48x-36
D. (H/p)(x)
X/x-1 / 2x/x+4
X/x-1 / x+4/2x
= X^2+4x/2x^2-2x
3.
A. (F+g)(3)
X^2+1 + x-4
3^2+1 + 3-4
10 -1
= 9
B. (f-g)(0)
X^2+1 - x-4
0+1 -0-4
1-4
= -3
C. (Fg)(-k)
(X^2+1) (x-4)
(-k^2+1) (-k-4)
K^3+4k^2-k-4
D. (F/g)(k-2)
X^2+1 /x-4
K-2^2+1 / k-2 -2
= K^2-4k+5 / k-4
Step-by-step explanation:
Answer:
q=17
Step-by-step explanation:
5q-10=75
add 10 to both sides to cancel out -10 on the left side
5q-10+10=75+10
5q=85
divide both sides by 5 to get rid of the 5 in 5q
5q/5=85/5
resulting in:
q=17
The first 5 Multiples of 7<span> are 35, 70, 105, 140, 175
</span>The first 5<span> Multiples of </span>20<span> are: </span>20<span>, 40, 60, 80, 100
</span>
Answer:
A. 84 pi feet^2
Step-by-step explanation:
So the lateral area is the rectangular piece on the net
In order for it to be an actual cylinder the 2 circles are congruent
Therefore the radi, area, circumference ect.. are the same.
So the only missing measurement we need to find the lateral area is the length of the rectangular piece
If you visualize a cylinder, the rectangular piece goes around the perimeter/circumference of the circle
So that means that the length of the rectangle is the circumference of the circle
Circumference = 2*pi*r
2 * pi * 6
= 12 pi
Then 7*12 pi
=84 pi
So the lateral area is 84 pi
:0
Area of a circle with diameter 14.
That means the radius is r=7 and the area is of course πr²
Answer: 49π
