Write an equation for the line that is perpendicular to Y=-3/7x+4 and passes through (-4,-5)
1 answer:
9514 1404 393
Answer:
y = 7/3x +13/3
Step-by-step explanation:
The equation of the given line is in slope-intercept form (y=mx+b), so we can see the slope (m) is -3/7. The slope of the perpendicular line is the opposite reciprocal of this, so is ...
m = -1/(-3/7) = 7/3
The y-intercept of the perpendicular line can be found from ...
b = y -mx
b = -5 -(7/3)(-4) = -15/3 +28/3 = 13/3
Then the slope-intercept equation of the perpendicular line is ...
y = mx +b
y = 7/3x +13/3
_____
<em>Additional comment</em>
You can get there a little faster using the point-slope form of the equation of a line. For slope m and point (h, k) that form is ...
y -k = m(x -h)
For our perpendicular line, the equation is ...
y +5 = 7/3(x +4)
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Answer:
Option C
Step-by-step explanation:
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case A) we have
In this expression the term of n is 6n
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has a coefficient of positive 6
case B) we have
In this expression the term of n is -5n
so
has a coefficient of negative 5
case C) we have
In this expression the term of n is n
so
has a coefficient of positive 1
case D) we have
In this expression the term of n is -n
so
has a coefficient of negative 1