Write an equation for the line that is perpendicular to Y=-3/7x+4 and passes through (-4,-5)
1 answer:
9514 1404 393
Answer:
y = 7/3x +13/3
Step-by-step explanation:
The equation of the given line is in slope-intercept form (y=mx+b), so we can see the slope (m) is -3/7. The slope of the perpendicular line is the opposite reciprocal of this, so is ...
m = -1/(-3/7) = 7/3
The y-intercept of the perpendicular line can be found from ...
b = y -mx
b = -5 -(7/3)(-4) = -15/3 +28/3 = 13/3
Then the slope-intercept equation of the perpendicular line is ...
y = mx +b
y = 7/3x +13/3
_____
<em>Additional comment</em>
You can get there a little faster using the point-slope form of the equation of a line. For slope m and point (h, k) that form is ...
y -k = m(x -h)
For our perpendicular line, the equation is ...
y +5 = 7/3(x +4)
You might be interested in
>
Hence, x = 0°, 180° and 360° <em><u>Ans</u></em>
Answer:
(a) The probability that the port handles less than 5 million tons of cargo per week is 0.7291.
(b) The probability that the port handles 3 or more million tons of cargo per week is 0.9664.
(c) The probability that the port handles between 3 million and 4 million tons of cargo per week is 0.2373.
(d) The number of tons of cargo per week that will require the port to extend its operating hours is 5.35 million tons.
Step-by-step explanation:
Let <em>X</em> = amount of cargo the port handles per week.
The random variable <em>X</em> is Normally distributed with parameters,
<em>μ</em> = 4.5 million
<em>σ</em> = 0.82 million
(a)
Compute the probability that the port handles less than 5 million tons of cargo per week as follows:
*Use a <em>z</em>-table for the probability.
Thus, the probability that the port handles less than 5 million tons of cargo per week is 0.7291.
(b)
Compute the probability that the port handles 3 or more million tons of cargo per week as follows:
*Use a <em>z</em>-table for the probability.
Thus, the probability that the port handles 3 or more million tons of cargo per week is 0.9664.
(c)
Compute the probability that the port handles between 3 million and 4 million tons of cargo per week as follows:
Thus, the probability that the port handles between 3 million and 4 million tons of cargo per week is 0.2373.
(d)
It is provided that P (X < x) = 0.85.
Then, P (Z < z) = 0.85.
The value of <em>z</em> for this probability is:
<em>z</em> = 1.04.
Compute the value of <em>x</em> as follows:
Thus, the number of tons of cargo per week that will require the port to extend its operating hours is 5.35 million tons.