Answer:

Step-by-step explanation:
Standard equation of a line is y = mx + b, where m is the slope.
Given line y = - 3x + 78, slope, m₁ = -3
<em><u>To find the line perpendicular to the given line.</u></em>
The lines are perpendicular to each other if the product of their slopes = - 1
That is,

So the slope of new line is


5x- 10 = 20
5x -10 +10 = 20 +10
5x = 30
5x/5 =30/5
x = 6
In this we know all three zeros and one point from which the graph pass.
So we will let specific cubic polynomial function of the form

As we know zeros are that point where we will get value of function equal to zero. So it is basically in form

SO in given question zeros are (2 , 0) , (3, 0) and (5,0)
So we can say

So required equation is

Now we have one point (0 , -5) from which graph passes.
So we say at x = 0 , f(x) = -5



So required equation of cubic polynomial is

For finding y - intercept we simply plugin x = 0 in given equation.
As we know at x = 0 , value of function is -5.
So y - intercept is -5.
Answer:
D
Step-by-step explanation:
because since there is no negative sign in front of the 3x we automatially know there is no reflection so that rules out answers A and B. Then, since 3 is greater than 1 we can determine that it is a stretch which would rule out answer C so the answer is D
4(-3)-3/(-3)+6
-12-3/-3+6
-12+1+6
-12+7
-5