By comparing the given shape with easier ones like triangles and rectangles we will see that the area of the shape is 8 square units.
<h3>
How to simplify the shape.</h3>
So the given shape is a little bit complex, but you can actually see that it is a triangle with a base of 8 units with a height of 4 units, where a rectangle of 2 in by 3 in was removed, and also removed a triangle of height of 2 inches and base of 2 inches.
Remember that:
- A triangle of height H and base B has an area = B*H/2
- A rectangle of length L and width W has an area = L*W.
Then the area of the given shape is:
A = 8*4/2 - 3*2 - 2*2/2
A = 16 - 6 - 2
A = 8
So the given shape has an area of 8 square units.
If you want to learn more about areas, you can read:
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Answer:
Step-by-step explanation:
we are given
(A)
(f×g)(x)=f(x)*g(x)
now, we can plug it
we can simplify it
(B)
Domain:
Firstly, we will find domain of f(x) , g(x) and (fxg)(x)
and then we can find common domain
Domain of f(x):
we know that f(x) is undefined at x=0
so, domain will be
∪
Domain of g(x):
Since, it is polynomial
so, it is defined for all real values of x
now, we can find common domain
so, domain will be
∪..............Answer
Range:
Firstly, we will find range of f(x) , g(x) and (fxg)(x)
and then we can find common range
Range of f(x):
we know that range is all possible values of y for which x is defined
since, horizontal asymptote will be at y=0
so, range is
∪
Range of g(x):
Since, it is quadratic equation
so, its range will be
now, we can find common range
so, range will be
∪.............Answer
When the base and the height of a triangle are the same. the hypotenuse is that number times sqrt2.
B and C are 7, so a would also be 7
We can get the Circumference of a circle with the diameter by using the formula:
Circumference = Diameter * pie
Where, pie = 22/7 = 3.14
Hope this helps!
Using the first derivative test, it is found that the graph is increasing on the interval is (-5, ∞).
<h3>What is Function?</h3>
A function is a process or a relation that associates each element 'a' of a non-empty set A , at least to a single element 'b' of another non-empty set B.
Here, the function is given by:
f(x) = x²/2 + 5x + 6
On differentiating both sides, with respect to x we get
f'(x) = x + 5
Then, we test the signal of the derivative, which is the first derivative test.
x + 5 ≥ 0
x ≥ -5
Thus, It is found that the Function is increasing on the interval is (-5, ∞).
Learn more about Function from:
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