1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
prisoha [69]
3 years ago
13

tim's piggy bank contains nickels and quarters worth $12.45. he has 69 coins in all. how many of each coins does he have?​

Mathematics
1 answer:
storchak [24]3 years ago
6 0

Answer: There can be multiple combos.

You might be interested in
A water fountain shoots up a jet of water
notsponge [240]
Could possibly be a geyser

3 0
3 years ago
How do I solve this?
Serhud [2]

Answer:

44.94

Step-by-step explanation:

Use trigonometric ratios to find the unknown side.

Since you are given the adjacent side and the opposite side is in question, use the tangent ratio.

tan(x) = opposite/adjacent

Replace the variables with given values.

tan(59) = x/27

Isolate the variable.

27tan(59) = x

Use a calculator to evaluate the answer.

x = 27tan(59) ≈ 44.94

Please mark as Brainliest! :)

8 0
4 years ago
The green truck was 5.5 meters long . How many centimeters was the truck?
vaieri [72.5K]
It would be 550 cm every 1 meter would be 100 cm so 5.5 will be 550cm

3 0
3 years ago
MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD
Varvara68 [4.7K]

Answer:

\sf \: Proved \: \angle \: OAD  \:  =  \angle \: OCD

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u>\angle \: OAD  \:  =  \angle \: OCD</u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

\angle \: OBD  \:  =  \angle \: OCD

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

\angle \: OBD  \:  =  \angle \: OAB \\ \angle \: OAB  \:  =  \angle \: OAD (same \: angles) \\ \angle \: OBD  \:  =  \angle \: OAD

Consider above prove as statement B

From Statement A & B we can say that

\angle \: OAD  \:  =  \angle \: OCD

<em>Thanks for joining brainly community!</em>

5 0
2 years ago
8x−5x+4−x=Ax+8. Anyone know
lora16 [44]

Answer:

a = \frac{2x-4}{x}

x = \frac{4}{-a+2}

Step-by-step explanation:

Let's solve for a.

8x−5x+4−x=ax+8

Step 1: Flip the equation.

ax+8=2x+4

Step 2: Add -8 to both sides.

ax+8+−8=2x+4+−8

ax=2x−4

Step 3: Divide both sides by x.

Let's solve for x.

8x−5x+4−x=ax+8

Step 1: Add -ax to both sides.

2x+4+−ax=ax+8+−ax

−ax+2x+4=8

Step 2: Add -4 to both sides.

−ax+2x+4+−4=8+−4

−ax+2x=4

Step 3: Factor out variable x.

x(−a+2)=4

Step 4: Divide both sides by -a+2.

Hope this helps!

brainliest?

6 0
2 years ago
Other questions:
  • Karen has 4h storyboiks. Karen's storybook collection is 2/3 of what Mary's collection is. How many storybooks do they have in a
    10·1 answer
  • What is 2/3 equivalent to?
    15·2 answers
  • Please help me solve this equation: B=3V/h solve for V
    7·1 answer
  • Please solve for x and explain every step in detail!!! it’s urgent
    6·1 answer
  • Rolling an even<br> number and the<br> coin landing on<br> heads
    8·2 answers
  • A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
    13·1 answer
  • Choose the congruence theorem that you would use to prove the triangles congruent.
    8·1 answer
  • Someone please help and tell me what Y is with which X. I don’t understand this and need a good grade.
    7·2 answers
  • Mark has 15 coins in dimes and quarters valuing $2.10 how many dimes does he have?
    11·1 answer
  • Are 22/32 equivalent to 11/16
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!