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3 years ago

Over what interval(s) is the function increasing?

Mathematics

2 answers:

pickupchik [31]3 years ago

8 0

The function is never increasing, always approaching y=5 but never reaching it. Therefore D is the correct answer

mash [69]3 years ago

8 0

Answer:

A function f is said to be decreasing if f(a) < f(b) when a > b. You want to look and see where the graph falls from left to right. The correct intervals are -∞ < x < ∞. so the answer is A

Step-by-step explanation:

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–243 = -9(10 + w) please help me

Verdich [7]

Answer:

w=17

Step-by-step explanation:

-243=-9(10+w)

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How do you solve -.8x + 40 - 8x - 35

makvit [3.9K]

Answer:

-16x + 5

Step-by-step explanation:

-8x + 40 -8x - 35

Collect like terms

-8x - 8x + 40 - 35

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3 years ago

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PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

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3 years ago