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Colt1911 [192]
3 years ago
15

Over what interval(s) is the function increasing?

Mathematics
2 answers:
pickupchik [31]3 years ago
8 0

The function is never increasing, always approaching y=5 but never reaching it. Therefore D is the correct answer

mash [69]3 years ago
8 0

Answer:

A function f is said to be decreasing if f(a) < f(b) when a > b. You want to look and see where the graph falls from left to right. The correct intervals are -∞ < x < ∞. so the answer is A

Step-by-step explanation:


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Filling in the boxes:
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Second row outside box: - or -1
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Expanded: -3c - 8

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3 years ago
Use: Ck = k! (n-k)!
Arlecino [84]

Answer:

3 ways.

Step-by-step explanation:

Combinations formula:

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In this question:

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3 years ago
According to the graph, what is the value of the constant in the equation below?
dedylja [7]

Answer:0.4

Step-by-step explanation:

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3 0
3 years ago
Write the following sum using summation notation -2/5+3/6-4/7........11/14
horrorfan [7]

Answer:

\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )

Step-by-step explanation:

Given: \frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}

To write: the given expression using summation notation

Solution:

Summation notation helps to write a long sum as a single expression.

In the summation notation, the variable \sum is called the index of summation.

Let x_1,x_2,x_3,...,x_n denote a set of n numbers.

Then in summation notation,

x_1+x_2+x_3+...+x_n=\sum_{i=1}^{n}x_i

\frac{-2}{5}=(-1)^1\left ( \frac{1+1}{1+4} \right )\\\frac{3}{6}=(-1)^2\left ( \frac{2+1}{2+4} \right )\\\frac{-4}{7}=(-1)^3\left ( \frac{3+1}{3+4} \right )\\.\\.\\.\\\frac{11}{14}=(-1)^10\left ( \frac{10+1}{10+4} \right )\\\therefore \frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}=\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )

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3 years ago
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Studentka2010 [4]
This is uselful! Thanks: ))
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