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3 years ago

The sum of two numbers is 21 The second number is six times the first number

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

5 0

Answer:

3+18=21

Step-by-step explanation:

first see the second number

let us assume as x & y

3+ (3×6)= 21

3+18=21

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Pls help I’ll brainlest <br> Asap

tiny-mole [99]

Answer:

C. slope

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1 year ago

Read 2 more answers

an item is regularly priced at $70. It is on sale for 30% off the regular price. how much in dollars is discounted from the regu

sleet_krkn [62]

$9 is discounted from the regular price. If you find the discounted price you get $21. Then subtract the 21 from 30 and you get 9

7 0

3 years ago

Which rule can you use to find the nth term of an arithmetic sequence in which the common difference is 5 and a12 = 63?

iren2701 [21]

Tn = a + (n-1)d

when n = 12, tn = 63

63 = a + (12-1)*5

a = 63 - 55 =8

tn or an
= 8 + (n-1) 5

= 3 + 5n

Hope this helps

4 0

3 years ago

Question 17/23

disa [49]

Answer:

60%

Step-by-step explanation:

Formula:

Percentage decrease = (amount of decrease)/(original price)

✪ Solve ✪

3.85 - 1.54/3.85 x 100

2.31/3.85 x 100 = 60%

Hence, Percent decrease is 60%

<em>~Lenvy</em>

6 0

2 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$