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eimsori [14]
3 years ago
10

A store sells 0,1,2,3,4,5,6,7,8 items daily with the same probability. Find the probability that one day you will sell more than

3 items.
Mathematics
1 answer:
olga2289 [7]3 years ago
5 0

Answer:

5/9

Step-by-step explanation:

Each number - 0 through 8 - has an equal probability of being the number of sales on a particular day.

There are 9 possibilities of equal likelihood, so each one has a probability of 1/9.

So we want the probability of the number of sales being 4, 5, 6, 7, or 8.

Those are 5 out of the 9 possibilities, so 5(1/9) = 5/9.

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The oil prices for 2014, rounded to the nearest dollar, were: 95, 101, 101, 102, 102, 106, 104, 97, 93, 84, 76, 59. what is the
kipiarov [429]
  • Interquartile Range (IQR) = Q_3-Q_1 , with Q_3 as the upper quartile and Q_1 as the lower quartile.

Firstly, rearrange the data so that it's in ascending order: \{59,76,84,93,95,97,101,101,102,102,104,106\}

Next, find the median:

\{59,76,84,93,95,\boxed{97,101,}101,102,102,104,106\}\\\\\frac{97+101}{2}\\\\\frac{198}{2}\\\\99

Now to find the lower quartile, find the "median" of the data set that's to the left of 99:

\{\overbrace{59,76,84,93,95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\{\overbrace{59,76,\boxed{84,93}95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\frac{84+93}{2}\\\\\frac{177}{2}\\\\88.5

Now to find the upper quartile, it's the similar process as finding the lower quartile, except that you are finding the "median" of the data set to the right of 99:

\{59,76,84,93,95,97,\overbrace{101,101,102,102,104,106}^{\textsf{to the right of the median}}\}\\\\\{59,76,84,93,95,97,\overbrace{101,101,\boxed{102,102} 104,106}^{\textsf{to the right of the median}}\}\\\\\frac{102+102}{2}\\\\\frac{204}{2}\\\\102

Now that we have the upper and lower quartile, subtract them:

102-88.5=13.5

<u>In short, the IQR of this data set is 13.5.</u>

8 0
3 years ago
What is the range of the following function:<br> y = 2(5^x) - 1
Orlov [11]
<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

or

Range: (2,∞+)

<h2>Why?</h2>

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

or

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

5 0
3 years ago
Find the value of 2^-3 times 3^-2
andreyandreev [35.5K]

Answer:

Step-by-step explanation:

2^-3=1/2^3

3^-2=1/3^2

(2^-3)(3^-2)=1/72

7 0
3 years ago
If Polly walks across the street to buy a cracker and the people who sell them only have one left and there's a long line out th
avanturin [10]
Let me break this down for you.

Polly walks across the street to buy a cracker (singular)

The sellers of the crackers only have 1 left to sell and there is a long line out the door.

Unless the owners have more frackers readily available to continue to sell, Polly will NOT get a cracker unfortunately.

Hope this helps! :)
3 0
4 years ago
Which expression is equivalent to 2÷3
mihalych1998 [28]
The answer should be d
4 0
3 years ago
Read 2 more answers
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