Given Data:
Time is taken = 24 seconds (to pass the pole)
Length of the train = 240 m
To Find:
Time to pass a 650m long platform =?
Solution:
The total distance traveled by train to cross a pole is equal to the length of the train; 240 m.
Distance = 240 m (in case of a pole)
Speed = distance/ time
Speed = 240 m/ 24 seconds
Speed = 10 m/s
So, the speed our train is traveling is 10 m/s.
Now, the time taken by the same train to cross a platform of 650 m can be calculated as,
Total distance = 650 m (platform length) + 240 m (train length)
Total distance = 890 m
Speed = distance/ time
Time = distance/ speed
Time = 890 m / 10m/s
Time = 89 seconds.
So, the time that it will take a train with a speed of 10 m/s and 240 m long to cross a plate form of 650 m is 89 seconds.
To know more about the relationship between speed, distance, and time, check out the link below:
brainly.com/question/23774048?referrer=searchResults
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Answer:
<G= 63 <J=108 <H=72 <K=117
Step-by-step explanation: The transformations don't change the angles of the shape in this case
C. 8.7 x 102
8.7 x 102= 887.4
Which is the largest product out of all the other equations.
Hope this helps!
Answer:
(3, 5)
Step-by-step explanation:
y = 2x - 1
3x + 2y = 19
In the second equation, substitute 2x - 1 in for y, since y equals 2x - 1 in the first equation. Solve for x.
3x + 2(2x - 1) = 19
3x + 4x - 2 = 19
7x - 2 = 19
7x - 2 + 2 = 19 + 2
7x = 21
7x/7 = 21/7
x = 3
Pick the first equation to solve for y since it says y =. Substitute 3 in for x.
y = 2x - 1
y = 2(3) - 1
y = 6 - 1
y = 5