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liberstina [14]

3 years ago

13

If the plane climbed 242 more feet at an angle of 2° degrees. How much further did the plane travel to reach its maximum height

in miles (b)?

1 answer:

melomori [17]3 years ago

8 0

Answer:

244

Step-by-step explanation:

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Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

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The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

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$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

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substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

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$(4+2x)=4+2(1.5)=7\ in$

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