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Alekssandra [29.7K]
2 years ago
11

The chord BC is a diameter of o​

Mathematics
1 answer:
s2008m [1.1K]2 years ago
4 0

Answer:

Step-by-step explanation:

It is true because, if the line BC goes through the midpoint O, this would mean it is the diameter of the circle.

So true.

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The value of a collectible is changing such that dv/dt = 2t/(sqrt(t^2+1)) given in 4/year, and t is the number of years from 200
alina1380 [7]

Answer:

Diviértete tratando de conseguirlo porque no sé, así que sí, pero no

Step-by-step explanation:

5 0
2 years ago
See attached picture, is there a way to enter equations or algebraic symbols?
coldgirl [10]

SOLUTIONS

Solve a given equations or algebraic symbols?

\begin{gathered} f(x)=x^2+2x \\ g(x)=1-x^2 \end{gathered}

(A)

\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}

(B)

\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}

(C)

\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}

(D)

\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}

5 0
1 year ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0
2 years ago
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Salsk061 [2.6K]

Answer:

$10.27

Step-by-step explanation:

H + F = $8, (7% of 8 is 0.56) [$8.56] + 20% = 10.272 --> $10.27

3 0
3 years ago
How to find the total distance traveled by a particle?
motikmotik
You need  to know the equation of motion for the particle.  
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3 years ago
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