Answer:
X¹= -2 + 2√33
X²= -2 - 2√33
Step-by-step explanation:
X × (X+2) = 32
X² + 2X = 32
X² + 2X - 32= 0
Δ=132
X= -2 ± 2√33
X¹= -2 + 2√33
X²= -2 - 2√33
(You can change the 2√33 to 11,5 if you want to)
Answer:1.7
Step-by-step explanation:
Answer:
Step-by-step explanation:
The quotient of two numbers is 305.4. Find the quotient if the divisor decreases 2 times and the divisor increases 3 times
x/y = 305.4
3x/(y/2) = 6x/y = 6*305.4 = 1832.4
Note that the question will be deleted soon because it is posted in a language other than English.
Обратите внимание, что вопрос будет удален в ближайшее время, потому что он размещен на языке, отличном от английского.
<h2>
Question:</h2>
Find k if (x+1) is a factor of 2x³ + kx² + 1
<h2>
Answer:</h2>
k = 1
<h2>
Step-by-step explanation:</h2>
The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.
<em>This is because;</em>
i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.
ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e
=> (-3)² - 9
=> (9) - 9 = 0
Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.
<em><u>From the question</u></em>
Given polynomial: 2x³ + kx² + 1
Given factor: x + 1.
Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e
2(-1)³ + k(-1)² + 1 = 0
2(-1) + k(1) + 1 = 0
-2 + k + 1 = 0
k - 1 = 0
k = 1
Therefore the value of k is 1.
