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3 years ago

What is the slope intercept form of the graph

Mathematics

1 answer:

Bingel [31]3 years ago

7 0

Answer:

y = x + 1

Step-by-step explanation:

y = mx + b

First, find the y-intercept. This is where the line intersects with the y-axis.

So, 1. -> y = mx + 1

Next, find the slope. For every 1/2 moving to the right, it also vertically increased by 1/2.

(1/2)/(1/2)

= 1 -> y = x + 1

Therefore, y = x + 1

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What is the equation of the line that passes through (1,3) and (2,5)

kramer

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-3}{2-1}\implies \cfrac{2}{1}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=2(x-1) \\\\\\ y-3=3x-2\implies y=2x+1$

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3 years ago

A Line Segment has the points (1,-2), and (3,-2). What are the new points after its dilated by a scale factor of 3/2 or 1.5

jeka57 [31]

Answer:

The new points after dilation are

(3/2, -3) and (9/2,-3)

Step-by-step explanation:

Here in this question, we want to give the new points of the line segment after it is dilated by a particular scale factor.

What is needed to be done here is to multiply the coordinates of the given line segment by the given scale factor.

Let’s call the positions on the line segment A and B.

Thus we have;

A = (1,-2) and B = (3,-2)

So by dilation, we multiply each of the specific data points by the scale factor and so we have;

A’ = (3/2, -3) and B’= (9/2,-3)

5 0

3 years ago

Whats 2+2+2+2+2+2+2+2+2+2

eimsori [14]

Answer:

Step-by-step explanation:

there are 10 2s

2×10 =20

7 0

3 years ago

Read 2 more answers

A package states that there are 60 calories in 12 crackers and 75 calories in 15 crackers. Since the relationship is proportiona

Masteriza [31]

Answer:

900 calories

Step-by-step explanation:

each cracker has 5 calories so you would times 5 by 180 which gets you 900

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3 years ago

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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Tomtit [17]

Apparently my answer was unclear the first time?

The flux of F across S is given by the surface integral,

$\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S$

Parameterize S by the vector-valued function r(u, v) defined by

$\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2. Then the surface element is

dS = n • dS

where n is the normal vector to the surface. Take it to be

$\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}$

The surface element reduces to

$\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv$

so that it points toward the origin at any point on S.

Then the integral with respect to u and v is

$\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS$

$=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS$

$=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}$

4 0

3 years ago