Answer:
122.30 cm²
Step-by-step explanation:
The figure is a triangular prism.
Formula for calculating surface area of a triangular prism = bh + L(S1 + S2 + S3)
Where,
b = 11 cm
h = 4.3 cm
S1 = 8 cm
S2 = 6 cm
S3 = 11 cm
L = 3 cm
Surface area = 11*4.3 + 3(8 + 6 + 11)
= 47.3 + 3(25)
= 122.3 cm²
Answer:
B(0) = 0 depth in inches 0 minutes after filling began is 0 ; that is at time = 0 ; depth = 0
B(1) represents the function one minutes after filling began.
B(9) = 11 depicts that the depth in inches if water 9 minutes after filling began is 11.
Step-by-step explanation:
The function gives depth of water in inches 7 minutes after filling began
A.) B(0)=0
The statement B(0) = 0 means the depth in inches 0 minutes after filling began is 0 ; that is at time = 0 ; depth = 0
B.) B(1)
B(1) represents the function one minutes after filling began.
C.B(9)=11
B(9) = 11 depicts that the depth in inches if water 9 minutes after filling began is 11.
Answer:
Equilibrium quantity = 26.92
Equilibrium price is $31.13
Step-by-step explanation:
Given :Demand function : 
Supply function : 
To Find : find the equilibrium quantity and equilibrium price.
Solution:
Demand function :
--A
Supply function :
---B
Now to find the equilibrium quantity and equilibrium price.
Solve A and B
Subtract B from A
So, equilibrium quantity = 26.92
Substitute the value of q in A
So, equilibrium price is $31.13
Answer:
M = 1/0.000121 = 8264.5 years
Step-by-step explanation:
M = − k ∫∞₀ teᵏᵗdt
To obtain this mean life, we'll use integration by parts to integrate the function ∫ teᵏᵗdt
∫udv = uv - ∫ vdu
u = t
du/dt = 1
du = dt
∫ dv = ∫ eᵏᵗdt
v = eᵏᵗ/k
∫udv = ∫ teᵏᵗdt
uv = teᵏᵗ/k
∫ vdu = eᵏᵗ/k
∫ teᵏᵗdt = (teᵏᵗ/k) - ∫eᵏᵗ/k
But, ∫eᵏᵗ/k = (1/k) ∫eᵏᵗ = (1/k²) eᵏᵗ = eᵏᵗ/k²
∫ teᵏᵗdt = (teᵏᵗ/k) - eᵏᵗ/k²
The rest of the calculation is done on paper in the image attached to this question
Answer:

Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values

