In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.
So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.
x + 1.5 = 14
x = 12.5 ounces
The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces
x + 1.5 = 16
x = 14.5 ounces
From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
Answer:
Factor and set each factor equal to zero. Y=x2+5x−8
Step-by-step explanation:
Answer:
No graph so we'll use the quadratic formula
x^2+x-4=0
a = 1
b = 1
c = -4
x = -1 +- sqr root (1^2 - 4 * 1 * -4) / 2
x = (-1 +- sqr root (1 +16) ) / 2
x1 = (-1 + sqr root (17)) / 2
x2 = (-1 - sqr root (17)) / 2
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
the equation would be C because
A would end up with a negative amount
B is more than she originally has to paint and
D has the wrong coefficient for <em> t</em>.
Answer:
1) B
Step-by-step explanation:
To get the volume of a cube, you multiply the length, width and height together. 4 x 7 x 8 = 224. 8 × 5 × 6 = 240. This means that chocolate box B has the larger volume.
