Answer:
and
Step-by-step explanation:
First make all the fractions into improper fractions
After doing that put them back into the problems
Problem 1)
÷ , plug in the improper fractions
÷
to divide, you need to flip the second fraction and multiply
· =
then reduce
Problem 2)
÷
Plug in improper fraction
÷
Then flip second fraction and multiply
·
Multiply
Reduce, or make it a mixed number
Answer:
a. closed under addition and multiplication
b. not closed under addition but closed under multiplication.
c. not closed under addition and multiplication
d. closed under addition and multiplication
e. not closed under addition but closed under multiplication
Step-by-step explanation:
a.
Let A be a set of all integers divisible by 5.
Let ∈A such that
Find
So, is divisible by 5.
So,
is divisible by 5.
Therefore, A is closed under addition and multiplication.
b.
Let A = { 2n +1 | n ∈ Z}
Let ∈A such that where m, n ∈ Z.
Find
So,
∉ A
So,
∈ A
Therefore, A is not closed under addition but A is closed under multiplication.
c.
Let but ∉A
Also,
∉A
Therefore, A is not closed under addition and multiplication.
d.
Let A = { 17n: n∈Z}
Let ∈ A such that
Find x + y and xy
So,
∈ A
Therefore, A is closed under addition and multiplication.
e.
Let A be the set of nonzero real numbers.
Let ∈ A such that
Find x + y
So,
∈ A
Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.
Therefore, A is not closed under addition but A is closed under multiplication.
Answer:
$32.25
Step-by-step explanation:
$53.75 ÷ 5 = $10.75
$10.75 × 3 = $32.25
Answer:
the less than of 1 is 36 more than the number
SOLUTION :
YES as well as NO , two equilateral ∆s can be congruent if any of their side matched to one another,
& CANNOT be congruent if any of their side didn't matched in terms of length (magnitude).
________________________________
MARK BRAINLIEST!