Answer:
We have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO.
Step-by-step explanation:
Let us assume that ABCD is a parallelogram having diagonals AC and BD.
We have to prove that in a parallelogram the diagonals bisect each other.
Assume that the diagonals of ABCD i.e. AC and BD intersect at point O.
Therefore, to prove that the diagonals AC and BD bisect each other, we have to first prove that Δ ABO and Δ CDO are congruent or Δ DAO and Δ BCO are congruent.
In symbol, we have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO. (Answer)
the least common multiple of 8 and 6 is 24
Answer:
96 degrees
Step-by-step explanation:
The angle bisectors splits the two angles mentioned down the middle so the 2 angles are equal to each other.
4x + 4 = 2(x + 13) Distribute the 2
4x + 4 = 2x + 26 Subtract 2x from both sides
2x + 4 = 26 Subtract 4 from both sides
2x = 22 Divide both sides by 2
x = 11 Plug that back into either the right side or the left side of the original equation
4x + 4
4(11) + 4
44 + 4
48. Each angle is 48 degrees. 48 + 48 is 96
