After 6 months, ammount left to pay = $1,840.34
On the seventh month, he payed of the debt with the interest (for one month).
Amount paid off at the seventh month = 1840.34(1 + 0.09/12) = 1840.34(1.0075) = 1854.14
Amount to have paid in the remaining 6 months = 314.83 x 6 = 1888.98
Amount saved = 1888.98 - 1854.14 = $34.84
Answer:
-4, 0, 3, 5
Step-by-step explanation:
The number line is being counted by ones. So when it's complete, it would be like this:
-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6
Hope this helps!!
Answer:
x = 13
Step-by-step explanation:
This is a simple algebraic problem. Since x must be left by itself in order to solve, we subtract 10 on both sides, giving us the final answer of x = 13.
Answer:
- compile the list of the 300 prostate patients considering various diversities i.e. various ages, various stages of the disease, various racial, social and economic background , various lifestyles as well.
- divide the sample into two groups, ensuring that each group is diversified equally
- Assign each group to the one of the two treatment procedures
- follow up on the different group after treatment
- compare the measurable variables from both groups after treatment in order to determine which treatment method is best
Step-by-step explanation:
A completely randomized design for this experiment can be carried out following the following steps
- compile the list of the 300 prostate patients considering various diversities i.e. various ages, various stages of the disease, various racial, social and economic background , various lifestyles as well.
- divide the sample into two groups, ensuring that each group is diversified equally
- Assign each group to the one of the two treatment procedures
- follow up on the different group after treatment
- compare the measurable variables from both groups after treatment in order to determine which treatment method is best
Answer:
Step-by-step explanation:
Because CB = 6 cm, we can find CD
Use Triangle CDB.
<BCD = <BCA - <ACD
<BCD = ?
<BCA = 90
<ACD = 60
<BCD = 90 - 60
<BCD = 30
Cos 30 = CD / CB
CD = Cos(30) * BC
CD = 5.196 cm
<A = 90 - ACD
<ACD = 60
<A = 90 - 60
<A = 30
Sin(<A) = CB / AB
AB = CB / sin(<A)
AB = 6 / 0.5
AB = 12
Area =1/2 CD * AB
Area = 1/2 * 5.196 * 12
Area = 31.18
