Answer:
The solution is
Step-by-step explanation:
The equation
can be rewritten as
and can be further simplified to
.
Now, taking the inverse sine of both sides we get:
The value of the right side on the interval is
,
which makes the equation (2)
solving for gives
which is our solution.
The range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].
<h3>What is the range of the function?</h3>Range of a function is the set of all the possible output values which are valid for that function.
The trigonometry function given in the problem is,
The above function can be written as,
The above function is the arc of sine function. The domain of arc of sine ranges from -1 to 1.
This is the domain of the inverse of sine function. In the attached image below, the graph of inverse sine function is plotted. The range of this function is,
Thus, the range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].
Learn more about the range of the function here;
