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Aleks04 [339]
3 years ago
8

Someone please help ASAP!!!

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0
3-1 is bigger than 1/4 because 3-1= 1/3
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Look at this graph.
Phoenix [80]

Answer:  y= 1/4 x + 500

Step-by-step explanation:

The slope is the difference in y-values divided by difference in x-values plus the starting constant value (500 on the graph)

700 - 600  is the difference in y-values = 100

800 - 400 is the difference in x-values  = 400

100/400 = 1/4

y = x/4 +500

7 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
Is the following conditional true?
kakasveta [241]

Answer:

Yes

Step-by-step explanation:

3 0
3 years ago
Determine the number of x-intercepts that appear on a graph of each function.
almond37 [142]

Answer:

not 2

Step-by-step explanation:

3 0
3 years ago
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7 0
4 years ago
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