To make calculation easier, we first multiply
1.35 × 100 = 135
then we need to find how many groups of 5 are there in 135.
to do so, we simply take
135 ÷ 5 = 27
therefore, the answer is <u>27.</u>
Answer: a^2x^2+9x^2+13x+6a
Step-by-step explanation:
(a^2+9) x^2+ 13x +6a
x^2(a^2+9)+13x+6a
Expand:x^2(a^2+9): a^2 x^2+9^2
x^2 a^2 +x^2*9
a^2 x^2+9x^2
a^2 x^2+9x^2+13x+6a
Answer:
7x-10
Step-by-step explanation:
At the end of the year, Juan has 52.71 more than 4 times his balance at the beginning. Okay, let's set this up.
4x + 52.71
(4 times) (52.71 more)
His ending was 172.90, so
4x + 52.71=172.90
4x= 120.19
x= 30.05
He had $30.05 at the beginning of the year.
The answer is A. -8
(step by step)
Do multiplication first. 7 * -8 = -56
Now subtraction. -56 - (-8) = -48
Hope this helped! ☺♥
