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2 years ago

Robin had 40 apples to give to 3 groups of children.

Mathematics

2 answers:

wariber [46]2 years ago

8 0

Answer:

23 apples

Step-by-step explanation:

1/8 of 40 = 5, 20 percent of 40 is 8. 8+4+5 = 17. 40-17 is 23

defon2 years ago

4 0

Answer: 23

Step-by-step explanation:

You might be interested in

What number is 90% of 350?

tatyana61 [14]

Answer:

315

Step-by-step explanation:

10% of 350 is 35 so 35 times 9 would equal 315

7 0

2 years ago

Solve the equation. 12=2+z/-6

Bogdan [553]

Answer:

$\boxed{\bold{z=-60}}$

Step-by-step explanation:

Switch Sides

$\bold{2+\frac{z}{-6}=12}$

Subtract 2 From Both Sides

$\bold{2+\frac{z}{-6}-2=12-2}$

Simplify

$\bold{\frac{z}{-6}=10}$

Multiply Both Sides By -6

$\bold{\frac{z\left(-6\right)}{-6}=10\left(-6\right)}$

Simplify

$\bold{z=-60}$

3 0

3 years ago

Read 2 more answers

Você tem $ 20 para gastar com o táxi. A corrida custa $5 mais $2,50d 2,50 por quilômetro.

Aloiza [94]

Answer:

$5 + 2.50k ≤ $20

6 kilometers

Step-by-step explanation:

Puedes viajar con $15 porque gastaste 5 en la tarifa base. 15 dividido por 2,5 es 6, por lo que puedes viajar 6 kilómetros con $20.

5 0

1 year ago

Please Help!!!!!! it's due this morning

zhuklara [117]

Answer:

Check the solution in both equations. The solution is ( − 1, 2). Solve the system by graphing: {− x + y = 12 x + y = 10 . Solve the system by graphing: {2x + y = 6 x + y = 1 . In all the systems of linear equations so far, the lines intersected and the solution was one point.

Hope it helps!!!

6 0

2 years ago

One day, eleven babies are born at a hospital. Assuming each baby has an equal chance of being a boy or girl, what is the probab

Andrews [41]

You only need to consider the situations where 10 or 11 of the babies are girls, then subtract those probabilities from 1. This will give probability that any other number up to 9 of the babies are girls.

Use binomial theorem.
$P(x=k) = (nCk) p^k (1-p)^{n-k}$

n = 11
k = 10,11
p = 1/2

$P(x=10) = 11 (\frac{1}{2})^{11} = \frac{11}{2048} \\ \\ P(x=11) = 1(\frac{1}{2})^{11} = \frac{1}{2048} \\ \\ P(x \leq 9) = 1 - \frac{11}{2048} - \frac{1}{2048} \\ \\ P(x \leq 9)=\frac{2036}{2048} = \frac{509}{512}$

4 0

3 years ago