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3 years ago

Robin had 40 apples to give to 3 groups of children.

Mathematics

2 answers:

wariber [46]3 years ago

8 0

Answer:

23 apples

Step-by-step explanation:

1/8 of 40 = 5, 20 percent of 40 is 8. 8+4+5 = 17. 40-17 is 23

defon3 years ago

4 0

Answer: 23

Step-by-step explanation:

You might be interested in

A 47-foot-long piece of pipe is to be cut into three pieces. The second piece is three times as long as the first piece, and the

DanielleElmas [232]

A = first piece, b = second piece, c = third piece

a + b + c = 47
b = 3a
c = 5a + 2

a + (3a) + (5a + 2) = 47.....combine like terms
9a + 2 = 47
9a = 47 - 2
9a = 45
a = 45/9
a = 5 ft

b = 3a.....b = 3(5)....b = 15 ft
c = 5a + 2....c = 5(5) + 2.....c = 25 + 2....c = 27 ft

longest piece (c) = 27 ft

7 0

3 years ago

Help solving this problem

amid [387]

2t + 5b = 20
8t + 3b = 29
Multiply the first equation by-4
-8t -20b = -80
8t + 3b = 29
-17b = -51
b = 3
Plug 3 in for b into either equation and solve for t.
2t + 5(3) = 20
2t + 15 = 20
2t = 5
Divide both sides by 2
t = 2.50

5 0

3 years ago

A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

7 0

3 years ago

Guys pls help me!!!!!!

kumpel [21]

Answer:

x=32

Step-by-step explanation:

7 0

3 years ago

Subtract.<br> (3r²s+ 4rs+2-16r²s²) - (7sr²+10-13r²s²)<br><br> Simplify answer. Do not factor

pentagon [3]

[- 3r²s² - 4sr² + 4rs - 8] is the resultant answer when we subtract the linear equation (7sr²+10-13r²s²) from (3r²s+ 4rs+2-16r²s²).

<h3>What are linear equations?</h3>

A linear equation in one variable is a mathematical expression for an equation with only one variable.
While any two real integers can represent A and B, the ambiguous variable x has just one possible value.
The formula is Ax + B = 0.
9x + 78 = 18 is an example of a linear equation with just one variable.

So, we have:

(3r²s+ 4rs+2-16r²s²) - (7sr²+10-13r²s²)

Now, calculate as follows:

= (3r²s+ 4rs+2-16r²s²) - (7sr²+10-13r²s²)
= 3r²s+ 4rs+2-16r²s² - 7sr²- 10 + 13r²s²
= 13r²s² - 16r²s² - 7sr² + 3r²s + 4rs - 10 + 2
= - 3r²s² - 4sr² + 4rs - 8

Therefore, [- 3r²s² - 4sr² + 4rs - 8] is the resultant answer when we subtract the linear equation (7sr²+10-13r²s²) from (3r²s+ 4rs+2-16r²s²).

Learn more about linear equations:

brainly.com/question/11897796

#SPJ13

7 0

1 year ago