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Furkat [3]
2 years ago
13

WILL MARK BRAINLIESTTT

Mathematics
2 answers:
Montano1993 [528]2 years ago
5 0
The answer is C 90 cm2
Serhud [2]2 years ago
4 0
The answer would be C.
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\lim\limits_{x\to\pm\infty}\dfrac{x^2+7x+12}{-x^2-3x+4}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\dfrac{7}{x}+\dfrac{12}{x^2}\right)}{x^2\left(-1-\dfrac{3}{x}+\dfrac{4}{x^2}\right)}=\dfrac{1}{-1}=-1\\\\\boxed{y=-1}

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Attached the solution with work shown.

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Step-by-step explanation:

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