If <em>x</em> = -1, you have
2(-1) + 3 cos(-1) + <em>e</em> ⁻¹ ≈ -0.0112136 < 0
and if <em>x</em> = 0, you have
2(0) + 3 cos(0) + <em>e</em> ⁰ = 4 > 0
The function <em>f(x)</em> = 2<em>x</em> + 3 cos(<em>x</em>) + <em>eˣ</em> is continuous over the real numbers, so the intermediate value theorem applies, and it says that there is some -1 < <em>c</em> < 0 such that <em>f(c)</em> = 0.
The slope of the line passing the points (1, 1) and (0, 0) is 1
<h3>Slope of a line</h3>
The formula for calculating the slope of a line is expressed as
Slope = y2-y1/x2-x1
Given the coordinate points (1, 1) and (0, 0)
Substitute the given coordinate points
Slope = 0-1/0-1
Slope = -1/-1
Slope =1
Hence the slope of the line passing the points (1, 1) and (0, 0) is 1
Learn more on slope of a line here: brainly.com/question/3493733
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Answer:
Step-by-step explanation:
I gather that you need to find the area of the sector and then subtract from it the area of the segment to get the area of the triangle (although there are other ways in which to find the area of the triangle).
The area of a sector is:
where our angle is given as 34, pi is 3.1415, and the radius is 5:
and if you multiply and divide that all out you get that the area of the sector is:
A = 7.417
Now subtract from it the area of the segment, 2.209. to get the area of the triangle:
7.417 - 2.209 = 5.208
Answer:
2 sqrt(3)
Step-by-step explanation:
Simplify the following:
sqrt(363) - 3 sqrt(27)
sqrt(27) = sqrt(3^3) = 3 sqrt(3):
sqrt(363) - 33 sqrt(3)
sqrt(363) = sqrt(3×11^2) = 11 sqrt(3):
11 sqrt(3) - 3×3 sqrt(3)
-3×3 = -9:
11 sqrt(3) + -9 sqrt(3)
11 sqrt(3) - 9 sqrt(3) = 2 sqrt(3):
Answer: 2 sqrt(3)