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3 years ago

Somebody please help asap

Mathematics

1 answer:

Elena L [17]3 years ago

6 0

Answer:

B. $4x^2 + \frac{3}{2}x - 7$

Step-by-step explanation:

$f(x) = \frac{x}{2} - 3$

$g(x) = 4x^2 + x - 4$

(f + g)(x) = f(x) - g(x)

= $\frac{x}{2} - 3 + 4x^2 + x - 4$

Add like terms

$= 4x^2 + \frac{x}{2} + x - 3 - 4$

$= 4x^2 + \frac{3x}{2} - 7$

$= 4x^2 + \frac{3}{2}x - 7$

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viktelen [127]

The expected value of the outcome of the bid is $0.18

So let's start by counting how many bids are placed up to a total of 160.

100*160 = 16000.

What will be your arbitrary bid? As each bid has an equal chance of success, the average of all bids is used. (One cent plus 160 dollars) / 2 = 80 dollars (rounded)

Your odds of winning are 1/16000 (1 bid out of 16000).

If you win, your profit is 1920 ($2000 minus $80.00).

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Your cost to enter the auction is $1, and your average winning offer is $0.12.

The result is $0.18 (0.12-1=-0.88).

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2 years ago

Dominic is buying supplies for his poetry class. He likes to write his poems in black ink, then decorate the pages with colorful

pychu [463]

Answer:

No, they do not.

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3 years ago

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Alex73 [517]

Answer:

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Step-by-step explanation:

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3 years ago

There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that e

notsponge [240]

Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

$P_{1}=\frac{7 \ girls}{9 \ students}$

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

$P_{2}=\frac{6 \ girls}{8 \ students}$

Then, the probability of the third girl:

$P_{3}=\frac{5 \ girls}{7 \ students}$

The fourth girl probability:

$P_{3}=\frac{4 \ girls}{6 \ students}$

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

$P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \ 28\%)$

Therefore, there's 28% probability that every student in the group is a girl.

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3 years ago

What is the measure of x?

zheka24 [161]

Answer:

Hello! answer: x = 68

Step-by-step explanation:

This is a complementary angle meaning it will add up to 90 degrees 90 - 22 = 68 therefore x = 68 HOPE THAT HELPS!

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3 years ago