the minimum (or lower-extreme) would be 50, since it is the lowest number.
the lower quartile would be 59, since 58 and 60 are the two middle numbers on the lower side, you would do 58+60 / 2.
the median would be 66, since 64 and 68 are the two middle numbers. you would do 64+68 / 2.
the upper quartile would be 74, since 72 and 76 are the two middle numbers on the upper side, you would do 72+76 / 2.
the maximum (or upper-extreme) would be 92 since it is the largest number.
to graph, put in your numbers at the bottom (i would probably count by twos). then plot your minimum, lower quartile, median, upper quartile, and maximum. next, draw a box around the lower quartile and upper quartile with the median inside the box. lastly, extend two lines from the left and right side of the box connecting to the minimum and maximum.
i hope this makes sense ! this is what goes through my head when i solve these kinds of problems lol
first, find the numeric value for 11/15 second to find theta, simply do the <em>inverse</em> cos (which is cos^-1) of the first answer. now you know theta, just do the sin of 90 - theta and that's it!
since you know whatr cos(theta) is, you just take the inverse cos of that number to get theta and 'reverse' cos, essentially. you are just solving for theta, by reversing the cos function with cos^-1 please mark as brainliest!
From the 3100 weekday bus traveler, 310 travelers will be
asked by the sales person. And for every 2.685 traveler questioned, a traveler will
say yes. So there will be 115 bus travelers that will use a laptop computer
while travelling.
