the minimum (or lower-extreme) would be 50, since it is the lowest number.
the lower quartile would be 59, since 58 and 60 are the two middle numbers on the lower side, you would do 58+60 / 2.
the median would be 66, since 64 and 68 are the two middle numbers. you would do 64+68 / 2.
the upper quartile would be 74, since 72 and 76 are the two middle numbers on the upper side, you would do 72+76 / 2.
the maximum (or upper-extreme) would be 92 since it is the largest number.
to graph, put in your numbers at the bottom (i would probably count by twos). then plot your minimum, lower quartile, median, upper quartile, and maximum. next, draw a box around the lower quartile and upper quartile with the median inside the box. lastly, extend two lines from the left and right side of the box connecting to the minimum and maximum.
i hope this makes sense ! this is what goes through my head when i solve these kinds of problems lol
The answer would be d , because you have to add how many of each fish to equal up to the sum of 420 . which is x y . so the first equation is x + y = 420 . then it says he bought 6 times as many parrotfish as he did angelfish so you would have to multiply x which represents angelfish by 6 . to get the second equation of y = 6x .
