Step-by-step explanation:
Given :-
The length of the garden 8m greater than 2 times the width.
Area of the garden is 280 m²
Let us consider the length as x and width as y.
Sp, we can day length as :-
x = 8 + 2y ---(1)
Now, we know that:-
Area of Rectangle = Length × Breadth
280 = x * y
We can replace the value of x now,
280 = y × ( 8 + 2y)
280 = 8y + 2y²
2y² + 8y - 280 = 0
y² + 4y - 140 = 0
Factorise it.
(y -10)(y + 14)
Cancelling -ve value, we get the width as 10 metres.
<u>Hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>:</u><u>)</u>
The initial term of this geometric series is 4, and the common ratio is -1/2. The sum is given by
The sum is
approximately 2.66.
Area of a triangle = (1/2)*base*height
For both of the triangles, you have the base (8.8 for the triangle on the left, 7.6 for the triangle on the right) and the side lengths, but not the height. But since both are isosceles triangles, you can find the height using the pythagorean theorem.
5.
First divide the triangle vertically into two triangles (see attached picture). Now you have two right triangles, you can apply the pythagorean theorem on either one of them to find the height. The pythagorean theorem says that for a right triangle, , where c is the hypotenuse and a and b are the sides of the triangle.
Substituting the given values and rounding to nearest tenth:
Now that you have the height, you can find the area of the entire triangle.
A = (1/2)*base*height
A = (1/2)*8.8*9.0 = 39.6
6.
Same procedure.
A = (1/2)*base*height
A = (1/2)*7.6*9.2 = 35.0
X=-33 y= 10
Leave first row the same multiply 2nd row by -1
-2x+8y=14
2x+2y=26
10y= 40
Y=4
-2x+8(10)=14
-2x+80=14