Answer:
It will take 10 minutes for the printer to print 240 pages.
Step-by-step explanation:
First, you have to find how many pages the printer prints in 1 minutes. whixh is 24. You can find this by simply dividing 96 by 4. Then, you divide 240 from 24, and get 10! Hope this helps!
Answer: ok so Let's simplify step-by-step.
r−3q+5p−(−4r−3q−8p)
Distribute the Negative Sign:
=r−3q+5p+−1(−4r−3q−8p)
=r+−3q+5p+−1(−4r)+−1(−3q)+−1(−8p)
=r+−3q+5p+4r+3q+8p
Combine Like Terms:
=r+−3q+5p+4r+3q+8p
=(5p+8p)+(−3q+3q)+(r+4r)
=13p+5r
Step-by-step explanation:
Answers:
x = 72
y = 83
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Explanation:
Angle VFG is 50 degrees. The angle adjacent to this is angle EFG which is 180-50 = 130 degrees.
Angle HDW is 77 degrees. The supplementary angle adjacent to this is 180-77 = 103 degrees which is angle EDH.
Pentagon EFGHD has the following five interior angles
- E = x
- F = 130
- G = 170
- H = 65
- D = 103
Note that angles F = 130 and D = 103 were angles EFG and EDH we calculated earlier.
For any pentagon, the interior angles always add to 180(n-2) = 180(5-2) = 180*3 = 540 degrees.
This means,
E+F+G+H+D = 540
x+130+170+65+103 = 540
x+468 = 540
x = 72
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Now focus your attention on triangle THS
We see that the interior angles are
The angle H is 65 degrees because it's paired with the other 65 degree angle shown. They are vertical angles.
For any triangle, the angles always add to 180
T+H+S = 180
y+65+32 = 180
y+97 = 180
y = 180-97
y = 83
The answer is 38,000. Lmk if u need an explanation
Answer with Step-by-step explanation:
Since we have given that
Initial velocity = 50 ft/sec =
Initial height of ball = 5 feet =
a. What type of function models the height (ℎ, in feet) of the ball after tt seconds?
As we know the function for height h with respect to time 't'.
b. Explain what is happening to the height of the ball as it travels over a period of time (in tt seconds).
What function models the height, ℎ (in feet), of the ball over a period of time (in tt seconds)?
if it travels over a period of time then time becomes continuous interval . so it will use integration over a period of time
Our function becomes,