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T (z) = 2/3z over z - 1/2
T(3) = 2/2.5 = 4/5 or 0.8
T(1/2) is indeterminate, he reason being that the denominator becomes zero. Division by zero gives an indeterminate result.
Answer:
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Step-by-step explanation:
Answer:
I can't see the numbers well, but the graph is decreasing from (-inf, minimum) and increasing from (minimum, inf). The minimum is the vertex. Hope this helps!
Step-by-step explanation:
Answer:
4th option
Step-by-step explanation:
Given
-
← expand denominator using FOIL
=
- 
Since the denominators are common, then subtract the numerators
= 
Answer:
<em>A=3 and B=6</em>
Step-by-step explanation:
<u>Increasing and Decreasing Intervals of Functions</u>
Given f(x) as a real function and f'(x) its first derivative.
If f'(a)>0 the function is increasing in x=a
If f'(a)<0 the function is decreasing in x=a
If f'(a)=0 the function has a critical point in x=a
As we can see, the critical points may define open intervals where the function has different behaviors.
We have

Computing the first derivative:

We find the critical points equating f'(x) to zero

Simplifying by -6

We get the critical points

They define the following intervals

Thus A=3 and B=6