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2 years ago

5

Mindy conducts an experiment with three quarters. She counts the number of heads and tails for each flip of the three quarters.

Mindy records the results in the table below.

1 answer:

valkas [14]2 years ago

4 0

Answer:

i don't have the table so no one can answer

Step-by-step explanation:

You might be interested in

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

2 years ago

MULTIPLE CHOICE LaShawn designs websites for local

Artemon [7]

A is the correct answer I just took the quiz

7 0

2 years ago

HELP!!!!!!ASAP!!!!!!

Grace [21]

Answer:

Im only in middle school, sorry

Step-by-step explanation:

I have tips tho!

always write information down, only useful ones, and not like "jimmy love to play basketball" kin of stuff.

Think it through, dont just guess.

Hope this helps i guess,

-yuko

5 0

2 years ago

What is the length of BC?<br> help asp

Sloan [31]

Answer:

The answer would be 22.

8 0

3 years ago

Need help with math question

lyudmila [28]

Answer:

7 18-inch wreaths

26 22-inch wreaths

Step-by-step explanation:

Let's say the number of 18-inch wreaths is x and the number of 22-inch wreaths is y.

We know that the number of 22-inch wreaths sold was 5 more than 3 times the number of 18-inch wreaths sold. We can write this into the expression as:

y = 5 + 3x

We also know that each 18-inch wreath was $20 and each 22-inch wreath was $25. The total cost was $790, so:

20x + 25y = 790

Now, let's substitute 5 + 3x in for y in the second equation:

20x + 25y = 790

20x + 25(5 + 3x) = 790

20x + 125 + 75x = 790

95x + 125 = 790

95x = 665

x = 7

Plug this value into y = 5 + 3x to find y:

y = 5 + 3x

y = 5 + 3 * 7 = 5 + 21 = 26

So, 7 18-inch wreaths were sold and 26 22-inch wreaths were sold.

6 0

3 years ago