Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
Hope this helps :)
Circumference = 2 pi r = 10
r = 10 / 2 pi
75% of the error = 0.75 * pi * (10 / 2pi)^2
= 5.968 square unts
6 to nearest square unit
100% = 70
1% = .7 (divide by 100)
12% = 8.4 (Multiply 1% by 12)
70 - 8.4 = 61.6 (New Price)
Hope this helped! Got any questions just ask!
X would be 90° ... every x is 90°
Answer:
1, 3
Step-by-step explanation:
theyre across from each other.
