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damaskus [11]
2 years ago
14

Does 5+4=8 and does 1+1=2​

Mathematics
1 answer:
stiks02 [169]2 years ago
3 0

Answer:

5 + 4 = 8 (False)

1 + 1 = 2 (True)

Step-by-step explanation:

<u>First Case:</u>

5+4=8

No this is not correct as when 5 is added to 4 then the result should be - (1+1+1+1+1) + (1+1+1+1)

= 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 +1

= 9

So this is not correct.

<u>Second</u><u> </u><u>C</u><u>ase</u><u>:</u>

1 + 1 = 2

Yes this is correct when 1 and 1 are added for two times it results in 2.

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What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
3 years ago
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