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Anastasy [175]
3 years ago
13

Compute 7,953,000 / 1000.

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

The answer is 7,953.

Step-by-step explanation :

When you divide like this you are basically being asked how many times something can go into something else. In this case, we are being asked to calculate how many times 1000 can go into 7,953,000. You can use basic math skills or do long division.

I'm going to go with the easier way, basic math skills.

There are three 0's in the back of the number 7,953,000, and notice 1000 has three 0's as well in the back. When you divide those three 0's in the back of both numbers basically cancel out. Well, what does that leave us with?

7953 is what were left with. The answer is 7,953.

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Solve the literal equation for y. 2x-4y=20
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2x -4y=20
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An airplane travels 3600 miles to Spain from an airport in New Jersey this trip takes 7.5 hours how far does the plane travel in
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Answer: The answer is 480

Step-by-step explanation: I got this because i divided 3600 by 7.5 and got 480 so im guessing the plane travels 480 miles in a hour.

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1/2 - [-1/4+2/3] how do you solve this value of the expression
Shkiper50 [21]

Answer:

1/12

Step-by-step explanation:

1/2-[-1/4+2/3]

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3 0
3 years ago
Suppose we want to choose 5 objects, without replacement, from 15 distinct objects.
goblinko [34]

15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.

Given that, suppose we want to choose 5 objects, without replacement, from 15 distinct objects.

<h3>What is a permutation?</h3>

A permutation is a mathematical calculation of the number of ways a particular set can be arranged, where the order of the arrangement matters.

Now, 13P_{5}= 13!/(13-5)!

= 13!/8! = 13x12x11x10x9= 1287 x 120 = 15,444

Therefore, 15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.

To learn more about the permutation visit:

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3 0
2 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
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