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2 years ago

Did you hear about the kidnapping?

Mathematics

1 answer:

Ganezh [65]2 years ago

6 0

Answer:

69,420

Step-by-step explanation:

._. you stole the egg from the chicken didn't you

he woke up bc you threw the egg at his face

kid + napping... ok i get it now im slow

You might be interested in

Name the geometric terms modeled by a wall <br> and floor

Gwar [14]

The geometric terms modelled will be:

1. Plane

2 Point

3Point

4Plane

5Line

6.Point

7Point

8 Plane

9.Plane

10.Line

It should be noted that a line is a one-dimensional figure, that has length but no width. It should be noted that a line is made of a set of points that is extended in opposite directions.

The plane is flat surface.

Learn more about line on:

brainly.com/question/1655368

#SPJ1

Name the geometric term modeled by each object.

1. wall of a classroom

2. a knot in a piece of thread

3. tip of a needle

4 floor of a room

5 edge of a table

6. tip of a pencil

7 far distant star

8 screen of a flat TV

9 sheet of paper

10. light beam

7 0

1 year ago

a rectangular has a perimeter of 50 centimeters if the width of the rectangular is 10 centimeters what is its length

kogti [31]

10+10=20 50-20=30/2= 15 cm for length

5 0

1 year ago

(1) (10 points) Find the characteristic polynomial of A (2) (5 points) Find all eigenvalues of A. You are allowed to use your ca

Yuri [45]

Answer:

Step-by-step explanation:

Since this question is lacking the matrix A, we will solve the question with the matrix

$\left[\begin{matrix}4 & -2 \\ 1 & 1 \end{matrix}\right]$

so we can illustrate how to solve the problem step by step.

a) The characteristic polynomial is defined by the equation $det(A-\lambdaI)=0$ where I is the identity matrix of appropiate size and lambda is a variable to be solved. In our case,

$\left|\left[\begin{matrix}4-\lamda & -2 \\ 1 & 1-\lambda \end{matrix}\right]\right|= 0 = (4-\lambda)(1-\lambda)+2 = \lambda^2-5\lambda+4+2 = \lambda^2-5\lambda+6$

So the characteristic polynomial is $\lambda^2-5\lambda+6=0$ .

b) The eigenvalues of the matrix are the roots of the characteristic polynomial. Note that

$\lambda^2-5\lambda+6=(\lambda-3)(\lambda-2) =0$

So $\lambda=3, \lambda=2$

c) To find the bases of each eigenspace, we replace the value of lambda and solve the homogeneus system(equalized to zero) of the resultant matrix. We will illustrate the process with one eigen value and the other one is left as an exercise.

If $\lambda=3$ we get the following matrix

$\left[\begin{matrix}1 & -2 \\ 1 & -2 \end{matrix}\right]$ .

Since both rows are equal, we have the equation

$x-2y=0$ . Thus x=2y. In this case, we get to choose y freely, so let's take y=1. Then x=2. So, the eigenvector that is a base for the eigenspace associated to the eigenvalue 3 is the vector (2,1)

For the case $\lambda=2$ , using the same process, we get the vector (1,1).

d) By definition, to diagonalize a matrix A is to find a diagonal matrix D and a matrix P such that $A=PDP^{-1}$ . We can construct matrix D and P by choosing the eigenvalues as the diagonal of matrix D. So, if we pick the eigen value 3 in the first column of D, we must put the correspondent eigenvector (2,1) in the first column of P. In this case, the matrices that we get are

$P=\left[\begin{matrix}2&1 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}3&0 \\ 0 & 2 \end{matrix}\right]$

This matrices are not unique, since they depend on the order in which we arrange the eigenvalues in the matrix D. Another pair or matrices that diagonalize A is

$P=\left[\begin{matrix}1&2 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}2&0 \\ 0 & 3 \end{matrix}\right]$

which is obtained by interchanging the eigenvalues on the diagonal and their respective eigenvectors

4 0

2 years ago

A circular clock face is stenciled along its edge. The radius of the clock is 12 centimeters, so the stenciling covers about cen

Inessa05 [86]

Answer:

6 srry if dis is wrong sis

Step-by-step explanation:

since the radius is 12 divide that by 2 and you get 6 which is the diameter.

so im guessing the answer is 6 idk i haven't done this inna min. i hope this was helpful <3

4 0

2 years ago

Read 2 more answers

Can you help stuck on this question for a while

stepladder [879]

Answer:

Option B

Step-by-step explanation:

Length of the rectangular sand box is given by the function,

F(x) = 3x³ + 6x - 2

Width of the sand box is represented by the function,

W(x) = 2x² - 4

Area function for the sand box will be,

Area of a rectangle = Length × Width

F(x) × W(x) = (3x³ + 6x - 2)(2x² - 4)

= 2x²(3x³ + 6x - 2) - 4(3x³ + 6x - 2)

= 6x⁵+ 12x³ - 4x²- 12x³- 24x + 8

= 6x⁵- 4x²- 24x + 8

Therefore, Area function will be represented by a polynomial degree of 5.

Option B will be the answer.

3 0

2 years ago