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abruzzese [7]
3 years ago
12

Help ASAP plz need answer

Mathematics
2 answers:
seraphim [82]3 years ago
8 0

u can download the gauthmath app. i promise it's very helpful :)

iren2701 [21]3 years ago
5 0

Answer:

y=1/4x+5

Step-by-step explanation:

............ ............

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Which of the following is an equivalent measurement to 500 grams? A. 50mg B.5,000mg C.50,000mg or D, 500,000mg
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A poll found that 52% of U.S. adult Twitter users get at least some news on Twitter. The standard error for this estimate was 2.
Leya [2.2K]

Answer:

The 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter is (0.46, 0.58). This means that we are 99% sure that the true proportion of all U.S. adult Twitter users who get some news on Twitter is between these two values.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A poll found that 52% of U.S. adult Twitter users get at least some news on Twitter. The standard error for this estimate was 2.4%

This means that:

\pi = 0.52, \sqrt{\frac{\pi(1-\pi)}{n}} = 0.024

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 - 2.575(0.024) = 0.46

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 + 2.575(0.024) = 0.58

The 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter is (0.46, 0.58). This means that we are 99% sure that the true proportion of all U.S. adult Twitter users who get some news on Twitter is between these two values.

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3 years ago
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