Oh boy. I don't know how to solve this off the top of my head so this answer may ramble a bit as I figure it out as I go along.
At least two numbers have to be close in value, one positive and one negative, in order for a+b+c to be true
Let's see, ABC=-12
If one letter was 4, 1, and -3 they would add to 2 and multiply to -12. I got these by just trying a bunch of combinations.
I'm pretty sure these are the right numbers, but which is which we need the AB+BC+AC formula to figure out.
IF: a=4 b=1 c=-3
4 -3 -12 = -11. Wow, first try, for reals!
A equals 4. B=1. C=-3
Would other combinations work?
a=1 b=-3 c=4
-3 + -12 + 4 = -11
Yes, other combinations work as well. Well, you have your numbers and two ways they can go. Hope this helps!
Answer:
x = -3/2, 1
Step-by-step explanation:
1. Use Rule of One
2. Take out the constants
3. Simplify 6/3 to 2
4. Use the product rule
5. Simplify
6. Move all terms to one side
7. Simplify
8. Split the second term
9. Factor out the common terms
10. Factor out the common term (again)
11. Solve for x
Answer:
x=−4+√22 or x=−4−√22
Step-by-step explanation:
Substitute all values in the quadratic formula.
Solve.
