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2 years ago

7

How to solve x+3y=3 and 2x-3y=-12

2 answers:

Ilya [14]2 years ago

4 0

$x+3y=3\\3y=-x+3\\\\2x-3y=-12\\-3y=-2x-12\\3y=2x+12\\\\-x+3=2x+12=3y\\-9=3x\\-3=x\\\\(-3)+3y=3\\3y=6\\y=2$

x = -3
y = 2

Sever21 [200]2 years ago

3 0

Get x on one side then you can use substitution
So, change x+3y=3 to x= -3y+3
Then plug in x to other equation to find y
2(-3y +3)-3y=-12
-6y + 6 -3y = -12
-9y = -18
Divide both sides by negative nine to find y
y = 2
Then plug in to original equation to find x
x + 3(2) = 3
x + 6 = 3
x = -3
So, y = 2 and x = -3

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3 years ago

I can’t figure out the solution I think it is y < -10

Olenka [21]

Hey there!

<em>With negatives ( $-$ ) you have to switch your symbol to the other way</em>
$\bold{\frac{y}{-2}\leq5}$
Firstly, substitute the $\bold{y\ value }$ as an invisible 1
So, now we have to flip the equation around
$\bold{\frac{-1}{2}y\leq5}$
We have to $\bold{multiply}$ by $\bold{-2}$ on each of your sides
$\bold{-2\times\frac{-1}{2}\leq-2\times5}$
$\bold{Cancel \ out:2\times\frac{-1}{2}y \ because \ it \ equal \ 1}$
$\bold{Keep: -2\times5 \ because \ it \ helps \ us \ find \ our \ answer}$
$\bold{-2\times5=-10}$
$\boxed{\boxed{\bold{Answer:y\geq-10}}}\checkmark$

Good luck on your assignment and enjoy your day!

~ $\frak{LoveYourselfFirst:)}$

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2 years ago