Answer:
270° rotation about point B'
Step-by-step explanation:
Point B' is common to the last two figures, so is the center of rotation. Each of the segments of the figure A"B'C"D" is rotated clockwise 90° from the corresponding segment of A'B'C'D'. A 90° clockwise rotation is the same as a 270° counterclockwise rotation. The appropriate choice is ...
a 270° rotation about point B'
Answer:
<u>x² + y² + 2y - 1 = 0</u>
Step-by-step explanation:
The general form of the equation for the circle:
x² + y² + ax + by + c = 0
Where: a, b and c are constants.
For the given equation:
x² + (y + 1)² = 2
∴ x² + (y + 1) (y+1) = 2
∴ x² + y² + 2y + 1 = 2 ⇒ subtract 2 from both sides
∴ x² + y² + 2y + 1 - 2 = 2 - 2
∴ x² + y² + 2y - 1 = 0
So, the general form of the equation for the circle:
<u>x² + y² + 2y - 1 = 0</u>
If 9 is greater than x, it can be displayed as x < 9. If 5 is less than x, it can be displayed as 5 < x. To show it fully, the answer is 5 < x < <span> 9. </span>
Answer:-
f(x) = 3 (5)^x
Replace x with 2:
f(2) = 3(5)^2 = 3(25) = 75