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Viktor [21]
3 years ago
13

For each triangle below find the side that marked with the letter.

Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

All to 1 decimal place

3) a = 11.4

4) b = 11.2

5) c = 4.5

6) e = 6.4

7) f = 30.8

8) g = 67.9

Step-by-step explanation:

Step-by-step explanation:

3) cos(18) = a/12

12xcos(18) = a

a = 11.4

4) tan(25) = b/24

b = 24xtan(25)

b = 11.2

5) cos(51) = c/7.2

c = 7.2xcos(51)

c = 4.5

6) sin(28) = e/13.6

e = 13.6 x sin(28)

e = 6.4

7) cos(47) = 21/f

f = 21/cos(47)

f = 30.8

8) sin(33) = 37/g

g = 37/sin(37)

g = 67.9

All to 1 decimal place

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4) You and a friend go out for lunch. Each of you paid $6.50 for the meal including a 6% sales tax.
noname [10]

Answer:6:11

Step-by-step explanation:

I hope this helps

8 0
3 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
1. If the length of a rectangle is 6 more than its width, and its perimeter is 48
Salsk061 [2.6K]

For this case we have that by definition, the perimeter of the rectangle is given by:

P = 2w + 2L

Where:

W: Is the width of the rectangle

L: is the length of the rectangle

According to the data we have:

L = 6 + w\\P = 48

Substituting:

48 = 2w + 2 (6 + w)\\48 = 2w + 12 + 2w\\48 = 4w + 12\\48-12 = 4w\\36 = 4w\\w = \frac {36} {4}\\w = 9

So, the width of the rectangle is 9 inches

L = 6 + 9 = 15

So, the length of the rectangle is 15 inches

Answer:

the width of the rectangle is 9 inches

the length of the rectangle is 15 inches

5 0
3 years ago
This is really improtant
Oduvanchick [21]
To determine the lines that are parallel, you will need to find the missing angle length in the pairs of supplementary angles (totaling 180 degree).

180 - 114 = 66 degrees
180 - 112 = 68 degrees

Using these you can see the lines that are parallel.  They have matching angle measurements.

c // f
d // e


4 0
3 years ago
Ahhh hi pls help <br> f(x)=-2x^2+3
nikklg [1K]

Answer:

Step-by-step explanation:

F(x) is another name for y

If you make a table of values, you can plot the coordinates of this quadratic equation.

When "x" is 0, y is 3

7 0
3 years ago
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