No. It’s A. There are 8 km per 5 miles. How many Miles are in 120 km? In other words, 120 km/ x miles. Find x. You cross multiply giving you 8x=600. Divide by 8 on each side. Giving you x=75. So your answer is A
The side lengths could be 10, 24 and 26 units.
We must first find the side lengths. We use the distance formula to do this.
For RT:
![d=\sqrt{(11--1)^2+(-1--1)^2} \\=\sqrt{(11+1)^2+(-1+1)^2} \\=\sqrt{12^2+0^2}=\sqrt{144}=12](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%2811--1%29%5E2%2B%28-1--1%29%5E2%7D%0A%5C%5C%3D%5Csqrt%7B%2811%2B1%29%5E2%2B%28-1%2B1%29%5E2%7D%0A%5C%5C%3D%5Csqrt%7B12%5E2%2B0%5E2%7D%3D%5Csqrt%7B144%7D%3D12)
For ST:
![d=\sqrt{(11-11)^2+(4--1)^2} \\=\sqrt{0^2+(4+1)^2}=\sqrt{5^2}=\sqrt{25}=5](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%2811-11%29%5E2%2B%284--1%29%5E2%7D%0A%5C%5C%3D%5Csqrt%7B0%5E2%2B%284%2B1%29%5E2%7D%3D%5Csqrt%7B5%5E2%7D%3D%5Csqrt%7B25%7D%3D5)
For TR:
![d=\sqrt{(11--1)^2+(4--1)^2} \\=\sqrt{(11+1)^2+(4+1)^2}=\sqrt{12^2+5^2}=\sqrt{144+25}=\sqrt{169}=13](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%2811--1%29%5E2%2B%284--1%29%5E2%7D%0A%5C%5C%3D%5Csqrt%7B%2811%2B1%29%5E2%2B%284%2B1%29%5E2%7D%3D%5Csqrt%7B12%5E2%2B5%5E2%7D%3D%5Csqrt%7B144%2B25%7D%3D%5Csqrt%7B169%7D%3D13)
Our side lengths, from least to greatest, are 5, 12 and 13.
To be similar but not congruent, the side lengths must have the same ratio between corresponding sides but not be the same length. 10, 24 and 26 are all 2x the original side lengths, so this works.
A dot plot is showing how many numbers are the same and a frequency chart shows the same thing just without dots.
Gimme a second. The answer is
C. 168 units 2
He was off by 9.5%, you just divide 5.43 by 6 then subtract that answer from 1 and you get your percentage