Answer:
0.0008032
Step-by-step explanation:
Hope this helps!
I answered a similar question for someone else. The absolute value of a complex number is called the modulus. This represents the DISTANCE to the origin from the point on the imaginary + real plane.
the real horizontal distance is 5 and the imaginary vertical distance is in this case 4 (from -4i) the distance is 4. So to figure out this just use the Pythagorean theorem.
5^2 + (4)^2 = c^2
25 +16 = c^2
c^2 = 41c = 6.4 So option D.
Answer:
One of the angles in the triangle might be 50.
AND
The length of the third side must be 11cm or smaller.
Step-by-step explanation:
-The triangle might be an equilateral triangle (having all the same sides and angles). False, since the triangle sum theorem states that all angles inside of a triangle must add up to 180, so an equilateral triangle would need to have all three angles at 60 degrees.
-One of the angles in the triangle must be 120 (false; it can be anything above 90, which is not only 120)
-The length of the third side must be 11cm or smaller. (True, Triangle Inequality Theorem)
-One of the angles in the triangle might be 50 (possibly, so very much true)
Yes, 5/60, 5 divided by 5=1. 60 divided by 5= 12. Leaving you with 1/12. Meaning that both fractions are equivalent
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
