Answer:
Minimum unit cost = 5,858
Step-by-step explanation:
Given the function : C(x)=x^2−520x+73458
To find the minimum unit cost :
Take the derivative of C(x) with respect to x
dC/dx = 2x - 520
Set = 0
2x - 520
2x = 520
x = 260
To minimize unit cost, 260 engines must be produced
Hence, minimum unit cost will be :
C(x)=x^2−520x+73458
Put x = 260
C(260) = 260^2−520(260) + 73458
= 5,858
Answer:
0^6= 1000000. The final answer is 25000000.
The answer is A. C=0 and + = 3
Answer:
It is easier to calculate stresses in beam and an exact measure of strength of steel. • If two beams are made of same material and comparing the “section modulus” ... section modulus will be tougher and more capable to withstand larger loads. ... earth pressures and all forces for the anchored sheet pile wall in figure 3 below.
Step-by-step explanation:
Twenty three times a number f
